MATH SOLVE

4 months ago

Q:
# This is confusing :(Solve the equation x^4-4x^3+6x^2-4x+5=0 is one of its roots is 2-i.

Accepted Solution

A:

Answer:x can be three things: 5, 1, -1Step-by-step explanation:dividend x4 - 4x3 - 6x2 + 4x + 5 - divisor * x3 x4 - 5x3 remainder x3 - 6x2 + 4x + 5 - divisor * x2 x3 - 5x2 remainder - x2 + 4x + 5 - divisor * -x1 - x2 + 5x remainder - x + 5 - divisor * -x0 - x + 5 remainder 0Quotient : x3+x2-x-1 Remainder: 0