Q:

This is confusing :(Solve the equation x^4-4x^3+6x^2-4x+5=0 is one of its roots is 2-i.

Accepted Solution

A:
Answer:x can be three things: 5, 1, -1Step-by-step explanation:dividend     x4  -  4x3  -  6x2  +  4x  +  5 - divisor  * x3     x4  -  5x3             remainder         x3  -  6x2  +  4x  +  5 - divisor  * x2         x3  -  5x2         remainder          -  x2  +  4x  +  5 - divisor  * -x1          -  x2  +  5x     remainder              -  x  +  5 - divisor  * -x0              -  x  +  5 remainder                    0Quotient :  x3+x2-x-1  Remainder:  0