Q:

Solve the system of equations. −9y+4x−20=0−7y+16x−80=0\begin{aligned} &-9y+4x - 20=0 \\\\ &-7y+16x-80=0 \end{aligned} ​ −9y+4x−20=0 −7y+16x−80=0 ​ what is the value of x and y

Accepted Solution

A:
Answer:(x, y) = (5, 0)Step-by-step explanation:[tex]\begin{aligned} &-9y+4x - 20=0 \\ &-7y+16x-80=0 \end{aligned}[/tex]Subtract 4 times the first equation from the second:   (-7y +16x -80) -4(-9y +4x -20) = (0) -4(0)   29y = 0 . . . . . simplify   y = 0 . . . . . . . .divide by 29   4x -20 = 0 . . . . substitute 0 for y in the first equation   x -5 = 0 . . . . . .divide by 4   x = 5 . . . . . . . . add 5The solution to this system is (x, y) = (5, 0).